Metamath Proof Explorer


Theorem n0moeu

Description: A case of equivalence of "at most one" and "only one". (Contributed by FL, 6-Dec-2010)

Ref Expression
Assertion n0moeu ⊢ A ≠ ∅ → ∃* x x ∈ A ↔ ∃! x x ∈ A

Proof

Step Hyp Ref Expression
1 n0 ⊢ A ≠ ∅ ↔ ∃ x x ∈ A
2 1 biimpi ⊢ A ≠ ∅ → ∃ x x ∈ A
3 2 biantrurd ⊢ A ≠ ∅ → ∃* x x ∈ A ↔ ∃ x x ∈ A ∧ ∃* x x ∈ A
4 df-eu ⊢ ∃! x x ∈ A ↔ ∃ x x ∈ A ∧ ∃* x x ∈ A
5 3 4 bitr4di ⊢ A ≠ ∅ → ∃* x x ∈ A ↔ ∃! x x ∈ A