Metamath Proof Explorer


Theorem ndmov

Description: The value of an operation outside its domain. (Contributed by NM, 24-Aug-1995)

Ref Expression
Hypothesis ndmov.1 ⊢ dom ⁡ F = S × S
Assertion ndmov ⊢ ¬ A ∈ S ∧ B ∈ S → A F B = ∅

Proof

Step Hyp Ref Expression
1 ndmov.1 ⊢ dom ⁡ F = S × S
2 ndmovg ⊢ dom ⁡ F = S × S ∧ ¬ A ∈ S ∧ B ∈ S → A F B = ∅
3 1 2 mpan ⊢ ¬ A ∈ S ∧ B ∈ S → A F B = ∅