Metamath Proof Explorer


Theorem necon3bid

Description: Deduction from equality to inequality. (Contributed by NM, 23-Feb-2005) (Proof shortened by Andrew Salmon, 25-May-2011)

Ref Expression
Hypothesis necon3bid.1 φA=BC=D
Assertion necon3bid φABCD

Proof

Step Hyp Ref Expression
1 necon3bid.1 φA=BC=D
2 df-ne AB¬A=B
3 1 necon3bbid φ¬A=BCD
4 2 3 bitrid φABCD