Metamath Proof Explorer


Theorem necon3bii

Description: Inference from equality to inequality. (Contributed by NM, 23-Feb-2005)

Ref Expression
Hypothesis necon3bii.1 ⊢ A = B ↔ C = D
Assertion necon3bii ⊢ A ≠ B ↔ C ≠ D

Proof

Step Hyp Ref Expression
1 necon3bii.1 ⊢ A = B ↔ C = D
2 1 necon3abii ⊢ A ≠ B ↔ ¬ C = D
3 df-ne ⊢ C ≠ D ↔ ¬ C = D
4 2 3 bitr4i ⊢ A ≠ B ↔ C ≠ D