Metamath Proof Explorer


Theorem negbday

Description: Negation of a surreal number preserves birthday. (Contributed by Scott Fenton, 8-Mar-2025)

Ref Expression
Assertion negbday ⊢ A ∈ No → bday ⁡ + s ⁡ A = bday ⁡ A

Proof

Step Hyp Ref Expression
1 negbdaylem ⊢ A ∈ No → bday ⁡ + s ⁡ A ⊆ bday ⁡ A
2 negnegs ⊢ A ∈ No → + s ⁡ + s ⁡ A = A
3 2 fveq2d ⊢ A ∈ No → bday ⁡ + s ⁡ + s ⁡ A = bday ⁡ A
4 negscl ⊢ A ∈ No → + s ⁡ A ∈ No
5 negbdaylem ⊢ + s ⁡ A ∈ No → bday ⁡ + s ⁡ + s ⁡ A ⊆ bday ⁡ + s ⁡ A
6 4 5 syl ⊢ A ∈ No → bday ⁡ + s ⁡ + s ⁡ A ⊆ bday ⁡ + s ⁡ A
7 3 6 eqsstrrd ⊢ A ∈ No → bday ⁡ A ⊆ bday ⁡ + s ⁡ A
8 1 7 eqssd ⊢ A ∈ No → bday ⁡ + s ⁡ A = bday ⁡ A