Metamath Proof Explorer


Theorem negsf1o

Description: Surreal negation is a bijection. (Contributed by Scott Fenton, 3-Feb-2025)

Ref Expression
Assertion negsf1o ⊢ + s : No ⟶ 1-1 onto No

Proof

Step Hyp Ref Expression
1 negsf ⊢ + s : No ⟶ No
2 negs11 ⊢ x ∈ No ∧ y ∈ No → + s ⁡ x = + s ⁡ y ↔ x = y
3 2 biimpd ⊢ x ∈ No ∧ y ∈ No → + s ⁡ x = + s ⁡ y → x = y
4 3 rgen2 ⊢ ∀ x ∈ No ∀ y ∈ No + s ⁡ x = + s ⁡ y → x = y
5 dff13 ⊢ + s : No ⟶ 1-1 No ↔ + s : No ⟶ No ∧ ∀ x ∈ No ∀ y ∈ No + s ⁡ x = + s ⁡ y → x = y
6 1 4 5 mpbir2an ⊢ + s : No ⟶ 1-1 No
7 negsfo ⊢ + s : No ⟶ onto No
8 df-f1o ⊢ + s : No ⟶ 1-1 onto No ↔ + s : No ⟶ 1-1 No ∧ + s : No ⟶ onto No
9 6 7 8 mpbir2an ⊢ + s : No ⟶ 1-1 onto No