Metamath Proof Explorer


Theorem nf5di

Description: Since the converse holds by a1i , this inference shows that we can represent a not-free hypothesis with either F/ x ph (inference form) or ( ph -> F/ x ph ) (deduction form). (Contributed by NM, 17-Aug-2018) (Proof shortened by Wolf Lammen, 10-Jul-2019)

Ref Expression
Hypothesis nf5di.1 φxφ
Assertion nf5di xφ

Proof

Step Hyp Ref Expression
1 nf5di.1 φxφ
2 1 nf5rd φφxφ
3 2 pm2.43i φxφ
4 3 nf5i xφ