Metamath Proof Explorer


Theorem oppchom

Description: Hom-sets of the opposite category. (Contributed by Mario Carneiro, 2-Jan-2017)

Ref Expression
Hypotheses oppchom.h H=HomC
oppchom.o O=oppCatC
Assertion oppchom XHomOY=YHX

Proof

Step Hyp Ref Expression
1 oppchom.h H=HomC
2 oppchom.o O=oppCatC
3 1 2 oppchomfval tposH=HomO
4 3 oveqi XtposHY=XHomOY
5 ovtpos XtposHY=YHX
6 4 5 eqtr3i XHomOY=YHX