Metamath Proof Explorer


Theorem oppchom

Description: Hom-sets of the opposite category. (Contributed by Mario Carneiro, 2-Jan-2017)

Ref Expression
Hypotheses oppchom.h ⊢ H = Hom ⁡ C
oppchom.o ⊢ O = oppCat ⁡ C
Assertion oppchom ⊢ X Hom ⁡ O Y = Y H X

Proof

Step Hyp Ref Expression
1 oppchom.h ⊢ H = Hom ⁡ C
2 oppchom.o ⊢ O = oppCat ⁡ C
3 1 2 oppchomfval ⊢ tpos H = Hom ⁡ O
4 3 oveqi ⊢ X tpos H Y = X Hom ⁡ O Y
5 ovtpos ⊢ X tpos H Y = Y H X
6 4 5 eqtr3i ⊢ X Hom ⁡ O Y = Y H X