Metamath Proof Explorer


Theorem oppf1

Description: Value of the object part of the opposite functor. (Contributed by Zhi Wang, 19-Nov-2025)

Ref Expression
Hypothesis oppf1.f φ F C Func D
Assertion oppf1 Could not format assertion : No typesetting found for |- ( ph -> ( 1st ` ( oppFunc ` F ) ) = ( 1st ` F ) ) with typecode |-

Proof

Step Hyp Ref Expression
1 oppf1.f φ F C Func D
2 oppfval2 Could not format ( F e. ( C Func D ) -> ( oppFunc ` F ) = <. ( 1st ` F ) , tpos ( 2nd ` F ) >. ) : No typesetting found for |- ( F e. ( C Func D ) -> ( oppFunc ` F ) = <. ( 1st ` F ) , tpos ( 2nd ` F ) >. ) with typecode |-
3 fvex 1 st F V
4 fvex 2 nd F V
5 4 tposex tpos 2 nd F V
6 3 5 op1std Could not format ( ( oppFunc ` F ) = <. ( 1st ` F ) , tpos ( 2nd ` F ) >. -> ( 1st ` ( oppFunc ` F ) ) = ( 1st ` F ) ) : No typesetting found for |- ( ( oppFunc ` F ) = <. ( 1st ` F ) , tpos ( 2nd ` F ) >. -> ( 1st ` ( oppFunc ` F ) ) = ( 1st ` F ) ) with typecode |-
7 1 2 6 3syl Could not format ( ph -> ( 1st ` ( oppFunc ` F ) ) = ( 1st ` F ) ) : No typesetting found for |- ( ph -> ( 1st ` ( oppFunc ` F ) ) = ( 1st ` F ) ) with typecode |-