Metamath Proof Explorer


Theorem parteq1i

Description: Equality theorem for partition, inference version. (Contributed by Peter Mazsa, 5-Oct-2021)

Ref Expression
Hypothesis parteq1i.1 R = S
Assertion parteq1i R Part A S Part A

Proof

Step Hyp Ref Expression
1 parteq1i.1 R = S
2 parteq1 R = S R Part A S Part A
3 1 2 ax-mp R Part A S Part A