Metamath Proof Explorer


Theorem preq2d

Description: Equality deduction for unordered pairs. (Contributed by NM, 19-Oct-2012)

Ref Expression
Hypothesis preq1d.1 ⊢ φ → A = B
Assertion preq2d ⊢ φ → C A = C B

Proof

Step Hyp Ref Expression
1 preq1d.1 ⊢ φ → A = B
2 preq2 ⊢ A = B → C A = C B
3 1 2 syl ⊢ φ → C A = C B