Metamath Proof Explorer


Theorem preq2d

Description: Equality deduction for unordered pairs. (Contributed by NM, 19-Oct-2012)

Ref Expression
Hypothesis preq1d.1 φA=B
Assertion preq2d φCA=CB

Proof

Step Hyp Ref Expression
1 preq1d.1 φA=B
2 preq2 A=BCA=CB
3 1 2 syl φCA=CB