Metamath Proof Explorer


Theorem prlngeu

Description: Given a line A and a point X not on A , a unique line parallel to A can be drawn through X . Theorem 12.13 of Schwabhauser p. 124. (Contributed by Thierry Arnoux, 5-Jul-2026)

Ref Expression
Hypotheses prlngeu.p ⊢ P = Base G
prlngeu.l ⊢ L = Line 𝒢 ⁡ G
prlngeu.r No typesetting found for |- .|| = ( parlnG ` G ) with typecode |-
prlngeu.g ⊢ φ → G ∈ 𝒢 Tarski
prlngeu.a ⊢ φ → A ∈ ran ⁡ L
prlngeu.x ⊢ φ → X ∈ P ∖ A
prlngeu.1 ⊢ φ → G ∈ 𝒢 Tarski E
Assertion prlngeu ⊢ φ → ∃! b ∈ ran ⁡ L A ∥ ˙ b ∧ X ∈ b

Proof

Step Hyp Ref Expression
1 prlngeu.p ⊢ P = Base G
2 prlngeu.l ⊢ L = Line 𝒢 ⁡ G
3 prlngeu.r Could not format .|| = ( parlnG ` G ) : No typesetting found for |- .|| = ( parlnG ` G ) with typecode |-
4 prlngeu.g ⊢ φ → G ∈ 𝒢 Tarski
5 prlngeu.a ⊢ φ → A ∈ ran ⁡ L
6 prlngeu.x ⊢ φ → X ∈ P ∖ A
7 prlngeu.1 ⊢ φ → G ∈ 𝒢 Tarski E
8 6 eldifad ⊢ φ → X ∈ P
9 1 2 3 4 5 8 prlngex ⊢ φ → ∃ b ∈ ran ⁡ L A ∥ ˙ b ∧ X ∈ b
10 1 2 3 4 5 6 7 prlngmo ⊢ φ → ∃* b ∈ ran ⁡ L A ∥ ˙ b ∧ X ∈ b
11 reu5 ⊢ ∃! b ∈ ran ⁡ L A ∥ ˙ b ∧ X ∈ b ↔ ∃ b ∈ ran ⁡ L A ∥ ˙ b ∧ X ∈ b ∧ ∃* b ∈ ran ⁡ L A ∥ ˙ b ∧ X ∈ b
12 9 10 11 sylanbrc ⊢ φ → ∃! b ∈ ran ⁡ L A ∥ ˙ b ∧ X ∈ b