Metamath Proof Explorer


Theorem prodeq1d

Description: Equality deduction for product. (Contributed by Scott Fenton, 4-Dec-2017)

Ref Expression
Hypothesis prodeq1d.1 φA=B
Assertion prodeq1d φkAC=kBC

Proof

Step Hyp Ref Expression
1 prodeq1d.1 φA=B
2 prodeq1 A=BkAC=kBC
3 1 2 syl φkAC=kBC