Metamath Proof Explorer


Theorem prodeq1d

Description: Equality deduction for product. (Contributed by Scott Fenton, 4-Dec-2017)

Ref Expression
Hypothesis prodeq1d.1 φ A = B
Assertion prodeq1d φ k A C = k B C

Proof

Step Hyp Ref Expression
1 prodeq1d.1 φ A = B
2 prodeq1 A = B k A C = k B C
3 1 2 syl φ k A C = k B C