Metamath Proof Explorer


Theorem prodeq1d

Description: Equality deduction for product. (Contributed by Scott Fenton, 4-Dec-2017)

Ref Expression
Hypothesis prodeq1d.1 ⊢ φ → A = B
Assertion prodeq1d ⊢ φ → ∏ k ∈ A C = ∏ k ∈ B C

Proof

Step Hyp Ref Expression
1 prodeq1d.1 ⊢ φ → A = B
2 prodeq1 ⊢ A = B → ∏ k ∈ A C = ∏ k ∈ B C
3 1 2 syl ⊢ φ → ∏ k ∈ A C = ∏ k ∈ B C