Metamath Proof Explorer


Theorem psseq2i

Description: An equality inference for the proper subclass relationship. (Contributed by NM, 9-Jun-2004)

Ref Expression
Hypothesis psseq1i.1 A=B
Assertion psseq2i CACB

Proof

Step Hyp Ref Expression
1 psseq1i.1 A=B
2 psseq2 A=BCACB
3 1 2 ax-mp CACB