Metamath Proof Explorer


Theorem psssdm

Description: Field of a subposet. (Contributed by FL, 19-Sep-2011) (Revised by Mario Carneiro, 9-Sep-2015)

Ref Expression
Hypothesis psssdm.1 ⊢ X = dom ⁡ R
Assertion psssdm ⊢ R ∈ PosetRel ∧ A ⊆ X → dom ⁡ R ∩ A × A = A

Proof

Step Hyp Ref Expression
1 psssdm.1 ⊢ X = dom ⁡ R
2 1 psssdm2 ⊢ R ∈ PosetRel → dom ⁡ R ∩ A × A = X ∩ A
3 sseqin2 ⊢ A ⊆ X ↔ X ∩ A = A
4 3 biimpi ⊢ A ⊆ X → X ∩ A = A
5 2 4 sylan9eq ⊢ R ∈ PosetRel ∧ A ⊆ X → dom ⁡ R ∩ A × A = A