Theorem qseq1d

Description: Equality theorem for quotient set, deduction form. (Contributed by Peter Mazsa, 27-May-2021)

	Ref	Expression
Hypothesis	qseq1d.1	$$⊢\phi \to A=B$$
Assertion	qseq1d	$$⊢\phi \to A/C=B/C$$

Proof

Step	Hyp	Ref	Expression
1		qseq1d.1	$$⊢\phi \to A=B$$
2		qseq1	$$⊢A=B\to A/C=B/C$$
3	1 2	syl	$$⊢\phi \to A/C=B/C$$