Metamath Proof Explorer


Theorem rals2d

Description: Deduction rule: Given "all some" applied to a class, you can extract the "there exists" part. Note that the witness must satisfy the antecedent ps , not merely be a member of A . (Contributed by David A. Wheeler, 20-Oct-2018) (Revised by David A. Wheeler, 12-Jul-2026)

Ref Expression
Hypothesis rals2d.1 ⊢ φ → ∀∃ x ∈ A ψ → χ
Assertion rals2d ⊢ φ → ∃ x ∈ A ψ

Proof

Step Hyp Ref Expression
1 rals2d.1 ⊢ φ → ∀∃ x ∈ A ψ → χ
2 df-rals ⊢ ∀∃ x ∈ A ψ → χ ↔ ∀ x ∈ A ψ → χ ∧ ∃ x ∈ A ψ
3 1 2 sylib ⊢ φ → ∀ x ∈ A ψ → χ ∧ ∃ x ∈ A ψ
4 3 simprd ⊢ φ → ∃ x ∈ A ψ