Metamath Proof Explorer


Theorem rexbi

Description: Distribute restricted quantification over a biconditional. (Contributed by Scott Fenton, 7-Aug-2024) (Proof shortened by Wolf Lammen, 3-Nov-2024)

Ref Expression
Assertion rexbi ⊢ ∀ x ∈ A φ ↔ ψ → ∃ x ∈ A φ ↔ ∃ x ∈ A ψ

Proof

Step Hyp Ref Expression
1 biimp ⊢ φ ↔ ψ → φ → ψ
2 1 ralimi ⊢ ∀ x ∈ A φ ↔ ψ → ∀ x ∈ A φ → ψ
3 rexim ⊢ ∀ x ∈ A φ → ψ → ∃ x ∈ A φ → ∃ x ∈ A ψ
4 2 3 syl ⊢ ∀ x ∈ A φ ↔ ψ → ∃ x ∈ A φ → ∃ x ∈ A ψ
5 biimpr ⊢ φ ↔ ψ → ψ → φ
6 5 ralimi ⊢ ∀ x ∈ A φ ↔ ψ → ∀ x ∈ A ψ → φ
7 rexim ⊢ ∀ x ∈ A ψ → φ → ∃ x ∈ A ψ → ∃ x ∈ A φ
8 6 7 syl ⊢ ∀ x ∈ A φ ↔ ψ → ∃ x ∈ A ψ → ∃ x ∈ A φ
9 4 8 impbid ⊢ ∀ x ∈ A φ ↔ ψ → ∃ x ∈ A φ ↔ ∃ x ∈ A ψ