Metamath Proof Explorer
Description: A ring homomorphism is injective if and only if its kernel is zero.
(Contributed by Jeff Madsen, 16-Jun-2011) (Revised by AV, 24-Jul-2026)
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Ref |
Expression |
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Hypotheses |
rhmkerinj.b |
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rhmkerinj.c |
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rhmkerinj.0 |
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rhmkerinj.z |
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Assertion |
rhmkerinj |
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Proof
| Step |
Hyp |
Ref |
Expression |
| 1 |
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rhmkerinj.b |
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| 2 |
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rhmkerinj.c |
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| 3 |
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rhmkerinj.0 |
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| 4 |
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rhmkerinj.z |
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| 5 |
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rhmghm |
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| 6 |
1 2 3 4
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kerf1ghm |
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| 7 |
5 6
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syl |
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