Metamath Proof Explorer


Theorem sb7fALT

Description: Alternate version of sb7f . (Contributed by NM, 26-Jul-2006) (Revised by Mario Carneiro, 6-Oct-2016) (Proof modification is discouraged.) (New usage is discouraged.)

Ref Expression
Hypotheses dfsb1.p9 θ x = y φ x x = y φ
sb7fALT.1 z φ
Assertion sb7fALT θ z z = y x x = z φ

Proof

Step Hyp Ref Expression
1 dfsb1.p9 θ x = y φ x x = y φ
2 sb7fALT.1 z φ
3 biid z = y x = z φ x x = z φ z z = y x = z φ x x = z φ z = y x = z φ x x = z φ z z = y x = z φ x x = z φ
4 biid z = y x x = z φ z z = y x x = z φ z = y x x = z φ z z = y x x = z φ
5 biid x = z φ x x = z φ x = z φ x x = z φ
6 5 2 sb5fALT x = z φ x x = z φ x x = z φ
7 3 4 6 sbbiiALT z = y x = z φ x x = z φ z z = y x = z φ x x = z φ z = y x x = z φ z z = y x x = z φ
8 1 3 2 sbco2ALT z = y x = z φ x x = z φ z z = y x = z φ x x = z φ θ
9 4 sb5ALT2 z = y x x = z φ z z = y x x = z φ z z = y x x = z φ
10 7 8 9 3bitr3i θ z z = y x x = z φ