Metamath Proof Explorer


Theorem sbc6

Description: An equivalence for class substitution. (Contributed by NM, 23-Aug-1993) (Proof shortened by Eric Schmidt, 17-Jan-2007)

Ref Expression
Hypothesis sbc6.1 ⊢ A ∈ V
Assertion sbc6 ⊢ [˙A / x]˙ φ ↔ ∀ x x = A → φ

Proof

Step Hyp Ref Expression
1 sbc6.1 ⊢ A ∈ V
2 sbc6g ⊢ A ∈ V → [˙A / x]˙ φ ↔ ∀ x x = A → φ
3 1 2 ax-mp ⊢ [˙A / x]˙ φ ↔ ∀ x x = A → φ