Metamath Proof Explorer


Theorem sbcel21v

Description: Class substitution into a membership relation. One direction of sbcel2gv that holds for proper classes. (Contributed by NM, 17-Aug-2018)

Ref Expression
Assertion sbcel21v ⊢ [˙B / x]˙ A ∈ x → A ∈ B

Proof

Step Hyp Ref Expression
1 sbcex ⊢ [˙B / x]˙ A ∈ x → B ∈ V
2 sbcel2gv ⊢ B ∈ V → [˙B / x]˙ A ∈ x ↔ A ∈ B
3 2 biimpd ⊢ B ∈ V → [˙B / x]˙ A ∈ x → A ∈ B
4 1 3 mpcom ⊢ [˙B / x]˙ A ∈ x → A ∈ B