Metamath Proof Explorer


Theorem sbthb

Description: Schroeder-Bernstein Theorem and its converse. (Contributed by NM, 8-Jun-1998)

Ref Expression
Assertion sbthb ⊢ A ≼ B ∧ B ≼ A ↔ A ≈ B

Proof

Step Hyp Ref Expression
1 sbth ⊢ A ≼ B ∧ B ≼ A → A ≈ B
2 endom ⊢ A ≈ B → A ≼ B
3 ensym ⊢ A ≈ B → B ≈ A
4 endom ⊢ B ≈ A → B ≼ A
5 3 4 syl ⊢ A ≈ B → B ≼ A
6 2 5 jca ⊢ A ≈ B → A ≼ B ∧ B ≼ A
7 1 6 impbii ⊢ A ≼ B ∧ B ≼ A ↔ A ≈ B