Metamath Proof Explorer


Theorem scottab

Description: Value of the Scott operation at a class abstraction. (Contributed by Rohan Ridenour, 14-Aug-2023)

Ref Expression
Hypothesis scottab.1 x=yφψ
Assertion scottab Scottx|φ=x|φyψrankxranky

Proof

Step Hyp Ref Expression
1 scottab.1 x=yφψ
2 nfv xψ
3 2 1 scottabf Scottx|φ=x|φyψrankxranky