Metamath Proof Explorer


Theorem scotteq

Description: Closed form of scotteqd . (Contributed by Rohan Ridenour, 9-Aug-2023)

Ref Expression
Assertion scotteq ⊢ A = B → Scott A = Scott B

Proof

Step Hyp Ref Expression
1 id ⊢ A = B → A = B
2 1 scotteqd ⊢ A = B → Scott A = Scott B