Metamath Proof Explorer


Theorem seqeq2d

Description: Equality deduction for the sequence builder operation. (Contributed by Mario Carneiro, 7-Sep-2013)

Ref Expression
Hypothesis seqeqd.1 ⊢ φ → A = B
Assertion seqeq2d ⊢ φ → seq M A F = seq M B F

Proof

Step Hyp Ref Expression
1 seqeqd.1 ⊢ φ → A = B
2 seqeq2 ⊢ A = B → seq M A F = seq M B F
3 1 2 syl ⊢ φ → seq M A F = seq M B F