Metamath Proof Explorer


Theorem sin2pi

Description: The sine of 2 _pi is 0. (Contributed by Paul Chapman, 23-Jan-2008)

Ref Expression
Assertion sin2pi sin 2 π = 0

Proof

Step Hyp Ref Expression
1 picn π
2 sin2t π sin 2 π = 2 sin π cos π
3 1 2 ax-mp sin 2 π = 2 sin π cos π
4 sinpi sin π = 0
5 cospi cos π = 1
6 4 5 oveq12i sin π cos π = 0 -1
7 neg1cn 1
8 7 mul02i 0 -1 = 0
9 6 8 eqtri sin π cos π = 0
10 9 oveq2i 2 sin π cos π = 2 0
11 2t0e0 2 0 = 0
12 10 11 eqtri 2 sin π cos π = 0
13 3 12 eqtri sin 2 π = 0