Metamath Proof Explorer


Theorem sq10e99m1

Description: The square of 10 is 99 plus 1. (Contributed by AV, 14-Jun-2021) (Revised by AV, 1-Aug-2021)

Ref Expression
Assertion sq10e99m1 ⊢ 10 2 = 99 + 1

Proof

Step Hyp Ref Expression
1 sq10 ⊢ 10 2 = 100
2 9nn0 ⊢ 9 ∈ ℕ 0
3 9p1e10 ⊢ 9 + 1 = 10
4 eqid ⊢ 99 = 99
5 2 3 4 decsucc ⊢ 99 + 1 = 100
6 1 5 eqtr4i ⊢ 10 2 = 99 + 1