Metamath Proof Explorer


Theorem sqabssubi

Description: Square of absolute value of difference. (Contributed by Steve Rodriguez, 20-Jan-2007)

Ref Expression
Hypotheses absvalsqi.1 ⊢ A ∈ ℂ
abssub.2 ⊢ B ∈ ℂ
Assertion sqabssubi ⊢ A − B 2 = A 2 + B 2 - 2 ⁢ ℜ ⁡ A ⁢ B ‾

Proof

Step Hyp Ref Expression
1 absvalsqi.1 ⊢ A ∈ ℂ
2 abssub.2 ⊢ B ∈ ℂ
3 sqabssub ⊢ A ∈ ℂ ∧ B ∈ ℂ → A − B 2 = A 2 + B 2 - 2 ⁢ ℜ ⁡ A ⁢ B ‾
4 1 2 3 mp2an ⊢ A − B 2 = A 2 + B 2 - 2 ⁢ ℜ ⁡ A ⁢ B ‾