Metamath Proof Explorer


Theorem sqrtmsqi

Description: Square root of square. (Contributed by NM, 2-Aug-1999)

Ref Expression
Hypothesis sqrtthi.1 ⊢ A ∈ ℝ
Assertion sqrtmsqi ⊢ 0 ≤ A → A ⁢ A = A

Proof

Step Hyp Ref Expression
1 sqrtthi.1 ⊢ A ∈ ℝ
2 sqrtmsq ⊢ A ∈ ℝ ∧ 0 ≤ A → A ⁢ A = A
3 1 2 mpan ⊢ 0 ≤ A → A ⁢ A = A