Metamath Proof Explorer


Theorem sqrtsqi

Description: Square root of square. (Contributed by NM, 11-Aug-1999)

Ref Expression
Hypothesis sqrtthi.1 A
Assertion sqrtsqi 0 A A 2 = A

Proof

Step Hyp Ref Expression
1 sqrtthi.1 A
2 sqrtsq A 0 A A 2 = A
3 1 2 mpan 0 A A 2 = A