Metamath Proof Explorer


Theorem sseqin2

Description: A relationship between subclass and intersection. Similar to Exercise 9 of TakeutiZaring p. 18. (Contributed by NM, 17-May-1994)

Ref Expression
Assertion sseqin2 ABBA=A

Proof

Step Hyp Ref Expression
1 df-ss ABAB=A
2 incom AB=BA
3 2 eqeq1i AB=ABA=A
4 1 3 bitri ABBA=A