Metamath Proof Explorer


Theorem ssneldd

Description: If an element is not in a class, it is also not in a subclass of that class. Deduction form. (Contributed by David Moews, 1-May-2017)

Ref Expression
Hypotheses ssneld.1 φAB
ssneldd.2 φ¬CB
Assertion ssneldd φ¬CA

Proof

Step Hyp Ref Expression
1 ssneld.1 φAB
2 ssneldd.2 φ¬CB
3 1 ssneld φ¬CB¬CA
4 2 3 mpd φ¬CA