Metamath Proof Explorer


Theorem subrgacl

Description: A subring is closed under addition. (Contributed by Mario Carneiro, 2-Dec-2014)

Ref Expression
Hypothesis subrgacl.p ⊢ + ˙ = + R
Assertion subrgacl ⊢ A ∈ SubRing ⁡ R ∧ X ∈ A ∧ Y ∈ A → X + ˙ Y ∈ A

Proof

Step Hyp Ref Expression
1 subrgacl.p ⊢ + ˙ = + R
2 subrgsubg ⊢ A ∈ SubRing ⁡ R → A ∈ SubGrp ⁡ R
3 1 subgcl ⊢ A ∈ SubGrp ⁡ R ∧ X ∈ A ∧ Y ∈ A → X + ˙ Y ∈ A
4 2 3 syl3an1 ⊢ A ∈ SubRing ⁡ R ∧ X ∈ A ∧ Y ∈ A → X + ˙ Y ∈ A