Metamath Proof Explorer


Theorem sumeq1i

Description: Equality inference for sum. (Contributed by NM, 2-Jan-2006)

Ref Expression
Hypothesis sumeq1i.1 A = B
Assertion sumeq1i k A C = k B C

Proof

Step Hyp Ref Expression
1 sumeq1i.1 A = B
2 sumeq1 A = B k A C = k B C
3 1 2 ax-mp k A C = k B C