Metamath Proof Explorer


Theorem 7p4e11

Description: 7 + 4 = 11. (Contributed by Mario Carneiro, 19-Apr-2015) (Revised by AV, 6-Sep-2021)

Ref Expression
Assertion 7p4e11 ( 7 + 4 ) = 1 1

Proof

Step Hyp Ref Expression
1 7nn0 7 ∈ ℕ0
2 3nn0 3 ∈ ℕ0
3 0nn0 0 ∈ ℕ0
4 df-4 4 = ( 3 + 1 )
5 1e0p1 1 = ( 0 + 1 )
6 7p3e10 ( 7 + 3 ) = 1 0
7 1 2 3 4 5 6 6p5lem ( 7 + 4 ) = 1 1