Metamath Proof Explorer


Theorem 8olt9o

Description: Ordinal 8 is less than ordinal 9. (Contributed by BTernaryTau, 17-Oct-2026)

Ref Expression
Assertion 8olt9o 8o ∈ 9o

Proof

Step Hyp Ref Expression
1 8on ⊢ 8o ∈ On
2 sucidg ⊢ ( 8o ∈ On → 8o ∈ suc 8o )
3 1 2 ax-mp ⊢ 8o ∈ suc 8o
4 df-9o ⊢ 9o = suc 8o
5 3 4 eleqtrri ⊢ 8o ∈ 9o