Metamath Proof Explorer


Theorem 9t3e27

Description: 9 times 3 equals 27. (Contributed by Mario Carneiro, 19-Apr-2015)

Ref Expression
Assertion 9t3e27 ( 9 · 3 ) = 2 7

Proof

Step Hyp Ref Expression
1 9nn0 ⊢ 9 ∈ ℕ0
2 2nn0 ⊢ 2 ∈ ℕ0
3 df-3 ⊢ 3 = ( 2 + 1 )
4 9t2e18 ⊢ ( 9 · 2 ) = 1 8
5 1nn0 ⊢ 1 ∈ ℕ0
6 8nn0 ⊢ 8 ∈ ℕ0
7 eqid ⊢ 1 8 = 1 8
8 1p1e2 ⊢ ( 1 + 1 ) = 2
9 7nn0 ⊢ 7 ∈ ℕ0
10 1 nn0cni ⊢ 9 ∈ ℂ
11 6 nn0cni ⊢ 8 ∈ ℂ
12 9p8e17 ⊢ ( 9 + 8 ) = 1 7
13 10 11 12 addcomli ⊢ ( 8 + 9 ) = 1 7
14 5 6 1 7 8 9 13 decaddci ⊢ ( 1 8 + 9 ) = 2 7
15 1 2 3 4 14 4t3lem ⊢ ( 9 · 3 ) = 2 7