Metamath Proof Explorer


Theorem acnum

Description: The Axiom of Choice implies that any set is numerable. (Contributed by BTernaryTau, 3-Jul-2026)

Ref Expression
Assertion acnum ( CHOICE → ( 𝐴𝑉𝐴 ∈ dom card ) )

Proof

Step Hyp Ref Expression
1 elex ( 𝐴𝑉𝐴 ∈ V )
2 dfac10 ( CHOICE ↔ dom card = V )
3 2 biimpi ( CHOICE → dom card = V )
4 3 eleq2d ( CHOICE → ( 𝐴 ∈ dom card ↔ 𝐴 ∈ V ) )
5 1 4 imbitrrid ( CHOICE → ( 𝐴𝑉𝐴 ∈ dom card ) )