Metamath Proof Explorer


Theorem alrple

Description: Show that A is less than B by showing that there is no positive bound on the difference. (Contributed by Mario Carneiro, 12-Jun-2014)

Ref Expression
Assertion alrple ( ( 𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ ) → ( 𝐴 ≤ 𝐵 ↔ ∀ 𝑥 ∈ ℝ+ 𝐴 ≤ ( 𝐵 + 𝑥 ) ) )

Proof

Step Hyp Ref Expression
1 rexr ⊢ ( 𝐴 ∈ ℝ → 𝐴 ∈ ℝ* )
2 xralrple ⊢ ( ( 𝐴 ∈ ℝ* ∧ 𝐵 ∈ ℝ ) → ( 𝐴 ≤ 𝐵 ↔ ∀ 𝑥 ∈ ℝ+ 𝐴 ≤ ( 𝐵 + 𝑥 ) ) )
3 1 2 sylan ⊢ ( ( 𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ ) → ( 𝐴 ≤ 𝐵 ↔ ∀ 𝑥 ∈ ℝ+ 𝐴 ≤ ( 𝐵 + 𝑥 ) ) )