Metamath Proof Explorer


Theorem axc4

Description: Show that the original axiom ax-c4 can be derived from ax-4 ( alim ), ax-10 ( hbn1 ), sp and propositional calculus. See ax4fromc4 for the rederivation of ax-4 from ax-c4 .

Part of the proof is based on the proof of Lemma 22 of Monk2 p. 114. (Contributed by NM, 21-May-2008) (Proof modification is discouraged.)

Ref Expression
Assertion axc4 ( ∀ 𝑥 ( ∀ 𝑥 𝜑𝜓 ) → ( ∀ 𝑥 𝜑 → ∀ 𝑥 𝜓 ) )

Proof

Step Hyp Ref Expression
1 sp ( ∀ 𝑥 ¬ ∀ 𝑥 𝜑 → ¬ ∀ 𝑥 𝜑 )
2 1 con2i ( ∀ 𝑥 𝜑 → ¬ ∀ 𝑥 ¬ ∀ 𝑥 𝜑 )
3 hbn1 ( ¬ ∀ 𝑥 ¬ ∀ 𝑥 𝜑 → ∀ 𝑥 ¬ ∀ 𝑥 ¬ ∀ 𝑥 𝜑 )
4 hbn1 ( ¬ ∀ 𝑥 𝜑 → ∀ 𝑥 ¬ ∀ 𝑥 𝜑 )
5 4 con1i ( ¬ ∀ 𝑥 ¬ ∀ 𝑥 𝜑 → ∀ 𝑥 𝜑 )
6 5 alimi ( ∀ 𝑥 ¬ ∀ 𝑥 ¬ ∀ 𝑥 𝜑 → ∀ 𝑥𝑥 𝜑 )
7 2 3 6 3syl ( ∀ 𝑥 𝜑 → ∀ 𝑥𝑥 𝜑 )
8 alim ( ∀ 𝑥 ( ∀ 𝑥 𝜑𝜓 ) → ( ∀ 𝑥𝑥 𝜑 → ∀ 𝑥 𝜓 ) )
9 7 8 syl5 ( ∀ 𝑥 ( ∀ 𝑥 𝜑𝜓 ) → ( ∀ 𝑥 𝜑 → ∀ 𝑥 𝜓 ) )