Metamath Proof Explorer


Theorem bj-ax6elem2

Description: Lemma for bj-ax6e . (Contributed by BJ, 22-Dec-2020) (Proof modification is discouraged.)

Ref Expression
Assertion bj-ax6elem2 ( ∀ 𝑥 𝑦 = 𝑧 → ∃ 𝑥 𝑥 = 𝑦 )

Proof

Step Hyp Ref Expression
1 ax6ev 𝑥 𝑥 = 𝑧
2 equeucl ( 𝑥 = 𝑧 → ( 𝑦 = 𝑧𝑥 = 𝑦 ) )
3 1 2 eximii 𝑥 ( 𝑦 = 𝑧𝑥 = 𝑦 )
4 3 19.35i ( ∀ 𝑥 𝑦 = 𝑧 → ∃ 𝑥 𝑥 = 𝑦 )