Metamath Proof Explorer


Theorem bj-dfrel2

Description: Alternate definition of relation. Exercise 2 of TakeutiZaring p. 25. (Contributed by NM, 29-Dec-1996) (Proof shortened by BJ, 16-Oct-2026) Do not use opabid2 . (Proof modification is discouraged.)

Ref Expression
Assertion bj-dfrel2 ( Rel 𝑅 ↔ ◡ ◡ 𝑅 = 𝑅 )

Proof

Step Hyp Ref Expression
1 bj-dfrel4v ⊢ ( Rel 𝑅 ↔ { ⟨ 𝑥 , 𝑦 ⟩ ∣ 𝑥 𝑅 𝑦 } = 𝑅 )
2 cnvcnv3 ⊢ ◡ ◡ 𝑅 = { ⟨ 𝑥 , 𝑦 ⟩ ∣ 𝑥 𝑅 𝑦 }
3 2 eqeq1i ⊢ ( ◡ ◡ 𝑅 = 𝑅 ↔ { ⟨ 𝑥 , 𝑦 ⟩ ∣ 𝑥 𝑅 𝑦 } = 𝑅 )
4 1 3 bitr4i ⊢ ( Rel 𝑅 ↔ ◡ ◡ 𝑅 = 𝑅 )