Metamath Proof Explorer


Theorem bj-nfdt

Description: Closed form of nf5d and nf5dh . (Contributed by BJ, 2-May-2019)

Ref Expression
Assertion bj-nfdt ( ∀ 𝑥 ( 𝜑 → ( 𝜓 → ∀ 𝑥 𝜓 ) ) → ( ( 𝜑 → ∀ 𝑥 𝜑 ) → ( 𝜑 → Ⅎ 𝑥 𝜓 ) ) )

Proof

Step Hyp Ref Expression
1 bj-nfdt0 ( ∀ 𝑥 ( 𝜑 → ( 𝜓 → ∀ 𝑥 𝜓 ) ) → ( ∀ 𝑥 𝜑 → Ⅎ 𝑥 𝜓 ) )
2 1 imim2d ( ∀ 𝑥 ( 𝜑 → ( 𝜓 → ∀ 𝑥 𝜓 ) ) → ( ( 𝜑 → ∀ 𝑥 𝜑 ) → ( 𝜑 → Ⅎ 𝑥 𝜓 ) ) )