Metamath Proof Explorer


Theorem chvarv

Description: Implicit substitution of y for x into a theorem. Usage of this theorem is discouraged because it depends on ax-13 . Use the weaker chvarvv if possible. (Contributed by NM, 20-Apr-1994) (Proof shortened by Wolf Lammen, 22-Apr-2018) (New usage is discouraged.)

Ref Expression
Hypotheses chvarv.1 ( 𝑥 = 𝑦 → ( 𝜑𝜓 ) )
chvarv.2 𝜑
Assertion chvarv 𝜓

Proof

Step Hyp Ref Expression
1 chvarv.1 ( 𝑥 = 𝑦 → ( 𝜑𝜓 ) )
2 chvarv.2 𝜑
3 nfv 𝑥 𝜓
4 3 1 2 chvar 𝜓