Metamath Proof Explorer


Theorem chvarv

Description: Implicit substitution of y for x into a theorem. Usage of this theorem is discouraged because it depends on ax-13 . Use the weaker chvarvv if possible. (Contributed by NM, 20-Apr-1994) (Proof shortened by Wolf Lammen, 22-Apr-2018) (New usage is discouraged.)

Ref Expression
Hypotheses chvarv.1
|- ( x = y -> ( ph <-> ps ) )
chvarv.2
|- ph
Assertion chvarv
|- ps

Proof

Step Hyp Ref Expression
1 chvarv.1
 |-  ( x = y -> ( ph <-> ps ) )
2 chvarv.2
 |-  ph
3 nfv
 |-  F/ x ps
4 3 1 2 chvar
 |-  ps