Metamath Proof Explorer


Theorem chvarvv

Description: Implicit substitution of y for x into a theorem. Version of chvarv with a disjoint variable condition, which does not require ax-13 . (Contributed by NM, 20-Apr-1994) (Revised by BJ, 31-May-2019)

Ref Expression
Hypotheses chvarvv.1
|- ( x = y -> ( ph <-> ps ) )
chvarvv.2
|- ph
Assertion chvarvv
|- ps

Proof

Step Hyp Ref Expression
1 chvarvv.1
 |-  ( x = y -> ( ph <-> ps ) )
2 chvarvv.2
 |-  ph
3 1 spvv
 |-  ( A. x ph -> ps )
4 3 2 mpg
 |-  ps