Metamath Proof Explorer


Theorem coeq2i

Description: Equality inference for composition of two classes. (Contributed by NM, 16-Nov-2000)

Ref Expression
Hypothesis coeq1i.1 ⊢ 𝐴 = 𝐵
Assertion coeq2i ( 𝐶 ∘ 𝐴 ) = ( 𝐶 ∘ 𝐵 )

Proof

Step Hyp Ref Expression
1 coeq1i.1 ⊢ 𝐴 = 𝐵
2 coeq2 ⊢ ( 𝐴 = 𝐵 → ( 𝐶 ∘ 𝐴 ) = ( 𝐶 ∘ 𝐵 ) )
3 1 2 ax-mp ⊢ ( 𝐶 ∘ 𝐴 ) = ( 𝐶 ∘ 𝐵 )